Advance Selenium Multiple Choice Questions – MCQ1

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a)  driver.waitForElement()

b)  new WebDriverWait().until(ExpectedConditions.elementToBeClickable())

c)  Thread.sleep()

d)  new WebDriverWait().until(ExpectedConditions.visibilityOfElementLocated())

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a)  Actions.doubleClick(element)

b)  WebElement.contextClick()

c)  Actions.moveToElement(element).click()

d)  Actions.contextClick(element)

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a)  driver.takeScreenshot()

b)  ((TakesScreenshot) driver).getScreenshotAs(OutputType.FILE)

c)  driver.getScreenshot()

d)  driver.captureScreen()

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Advance Selenium Multiple Choice Answers – MCQ1

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Selenium cannot handle security testing on its own. However, it can assist in certain aspects of security testing when integrated with specialized security tools.



















JMeter Multiple Choice Answers – MCQ1

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JMeter Multiple Choice Questions – MCQ1

























JMeter Multiple Choice Questions – MCQ1

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Jenkins Multiple Choice Answers – MCQ2

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Jenkins Multiple Choice Questions – MCQ2

























Jenkins Multiple Choice Questions – MCQ2

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SQL Multiple Choice Answers – MCQ3

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SQL Multiple Choice Questions – MCQ3

























SQL Multiple Choice Questions – MCQ3

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ALTER TABLE Employees ADD CHECK (Age >= 18);

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UPDATE Products SET Price = Price * 1.1 WHERE Price < 100 OR Price > 200;

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SELECT Name FROM Employees WHERE NOT (Age < 30 AND Department = 'Sales');

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SELECT * FROM Employees WHERE Department = 'HR' XOR Department = 'Finance';

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UPDATE Employees SET Salary *= 2 WHERE YearsOfExperience > 5;

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SELECT Department, COUNT(*) FROM Employees GROUP BY Salary;

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SELECT AVG(Salary) AS AverageSalary FROM Employees HAVING AverageSalary > 50000;

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SELECT Name, Department, COUNT(*) FROM Employees WHERE Department = 'Sales' GROUP BY Department;

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SELECT Department, SUM(Salary) FROM Employees GROUP BY Department HAVING COUNT(*) > 5;

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SELECT * FROM Employees ORDER BY 3;

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SELECT Department, MAX(Salary) FROM Employees WHERE MAX(Salary) > 50000 GROUP BY Department;

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SELECT Department, COUNT(EmployeeID) FROM Employees GROUP BY Department HAVING COUNT(EmployeeID) > ALL (SELECT COUNT(EmployeeID) FROM Employees GROUP BY Department);

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SELECT Department, COUNT(*) AS TotalEmployees FROM Employees GROUP BY Department HAVING TotalEmployees > 5 ORDER BY TotalEmployees;

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SQL Multiple Choice Questions – MCQ2
SQL Multiple Choice Questions – MCQ3 

Jenkins Multiple Choice Answers – MCQ1

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Jenkins Multiple Choice Questions – MCQ1

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